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98 tigershark
July 24th, 2009, 04:56 AM
How much more does a pound of air weight at 32 degrees than at 90 degrees?

98 tigershark:fluffy:

joecar
July 24th, 2009, 06:02 AM
1lb of air always weighs 1lb regardless of its temperature...

:)

a given mass of air at lower temperature occupies less volume than at higher temperature...

Are you asking how does the density of air change with temperature...?

98 tigershark
July 24th, 2009, 07:05 AM
Hey Joe, you are right of course. I was having a little fun.
With that said a pound of warm air wont fit into the same space as a pound of cold air.
98 tigershark


1lb of air always weighs 1lb regardless of its temperature...

:)

a given mass of air at lower temperature occupies less volume than at higher temperature...

Are you asking how does the density of air change with temperature...?

joecar
July 24th, 2009, 11:04 AM
lol... it was a trick question...;)

assuming pressure stays constant, then from PV = nRT we see: V/T = constant...

so then: V1/T1 = V2/T2

and then: V2/V1 = T2/T1

Going from 32°F (273.15K) to 90°F (305.37K): V2/V1 = 305.37K/273.15K = 1.118

So if a given mass of air goes from 32°F to 90°F at constant pressure (i.e. the volume is allowed to change), the volume increases by a factor of 1.118 (i.e. increases by 11.8%).

mr.prick
July 24th, 2009, 11:14 AM
lol... it was a trick question...;)

assuming pressure stays constant, then from PV = nRT we see: V/T = constant...

so then: V1/T1 = V2/T2

and then: V2/V1 = T2/T1

Going from 32°F (273.15K) to 90°F (305.37K): V2/V1 = 305.37K/273.15K = 1.118

So if a given mass of air goes from 32°F to 90°F at constant pressure (i.e. the volume is allowed to change), the volume increases by a factor of 1.118 (i.e. increases by 11.8%).

But can you guess my weight? :laugh:

redhardsupra
July 24th, 2009, 12:17 PM
check this baby out:
http://www89.wolframalpha.com/input/?i=air+density+at+30kpa+and+300K

joecar
July 24th, 2009, 12:24 PM
check this baby out:
http://www89.wolframalpha.com/input/?i=air+density+at+30kpa+and+300KYeah, he's going to take over the world with Alpha... :hihi:

nevinsb
July 25th, 2009, 11:04 AM
So which weighs more, a pound of feathers or a pound of gold?

redhardsupra
July 25th, 2009, 11:09 AM
i dunno, drop both of them on your foot and tell me how equal they feel ;)

98 tigershark
July 26th, 2009, 03:38 AM
216Lbs:throw::throw::throw:

But can you guess my weight? :laugh:

mr.prick
July 26th, 2009, 03:40 AM
216Lbs:throw::throw::throw:

Lower

98 tigershark
July 26th, 2009, 03:42 AM
186Lbs on a warm day?
:hihi::hihi::fluffy:

Lower

mr.prick
July 26th, 2009, 04:01 AM
A little lower. :hihi:

98 tigershark
July 26th, 2009, 04:11 AM
How much does a pound of air weight was somewhat for fun but! On older IE 1997-2004 I believe the IAT sensor is closer to the motor than the MAF and the MAF measures the weight of the air as it is taken in (G/S or Lbs and Hour). At start up after you have run your car for a while the motor compartment can give a much higher IAT temp reading at startup(less dense air by quite a bit). This was solved in later models were as the MAF and the IAT are one. I think the IAT needs to be exactly or as close to were the MAF is since it is measuring weight of the air. As Joe pointed out there is a difference in the volume at different temps. Of course a pound of air weights a pound but the temp will determine how much air by weight will fit into the cylinder. So it would seem the closer to the MAF the IAT sensor is the more accurate the PCM can compute the correct mass entering the cylinder along with the other sensors. The cylinder size is finite but the amount of the weight of air in the cylinder is a variable.
98 tigershark


lol... it was a trick question...;)

assuming pressure stays constant, then from PV = nRT we see: V/T = constant...

so then: V1/T1 = V2/T2

and then: V2/V1 = T2/T1

Going from 32°F (273.15K) to 90°F (305.37K): V2/V1 = 305.37K/273.15K = 1.118

So if a given mass of air goes from 32°F to 90°F at constant pressure (i.e. the volume is allowed to change), the volume increases by a factor of 1.118 (i.e. increases by 11.8%).