continuing the example...
Then after calculating it needs 0.2 grams fuel, the PCM looks up the injector flowrate table to see how much the injector flows...
let say the injector flows 2 grams/second... to deliver 0.2 grams the injector would have to be opened for 0.1 second (i.e. divide 0.2 g/s by 2)...
so by firing the injector for 0.1 second will, after combustion (assuming no misfire) cause the wideband to measured the AFR to be 10:1 assuming the VE table is correct.
[I don't know of any injectors having a flowrate as low as 2 g/s... I used this for the example calculation only]...
[and an injector on time of 0.1 s would exceed the available time (i.e. 2 crank revolutions) and so would exceed 100% injector duty cycle].
:)