Before asking for help, please read this.
Paul next guy wanna know if the injection time is this right here:
* 11 OLDRFPER TIME BETWEEN REFERENCE PULSES (MSB)
* 12 +1 OLDRFPER TIME BETWEEN REFERENCE PULSES (LSB)
************************ MSEC = ([N11] * 256 + [N12]) / 65,536
This information is contained in A135.DS that matches my powerful Chevrolet Kadett GL 1.8 EFI Petrol.
I mounted the macro and now need to make sure if that's right. As to factor too have doubts, did seguite:
TI = ((11 * 256) + 12) / 65536, the result was 0.043151855. Is that correct?
I ask this because I want is to calculate consumption liters per hour and according to information I passed the time should be used for injection.
Besides, you know the formula to calculate the consumption of liters per hour at injection time?
Thanks!
"Reference Pulses" refers to the pulses from the crank sensor on the flywheel and is used to calculate RPM.
It provides a higher resolution signal than the previous byte, which only shows RPM in increments of 25.
The formula is actually
((11*256)+12)*65.536 (sixty-five point five three six) = 43.151855
To convert references pulses to RPM you need to do this (assuming the crank trigger has 60 teeth):
One complete revolution will take 43.151855*60 teeth = 2589ms
So in 1 millisecond the crank will complete 1/2589 revolutions.
Multiply that by 60,000 to convert milliseconds to minutes and get rpm = 23 rpm
23 rpm seems a bit low so maybe your crank does not have 60 teeth.
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Injector pulse width is defined here:
36 BPW BASE PULSE WIDTH (MSB)
37 BPW+1 BASE PULSE WIDTH (LSB)
mSEC = ([N36]*256 + [N37])/65.536
To convert from pulse width to fuel flow in liters you must know the "flow rate" of your injectors.
Regards
Paul
Before asking for help, please read this.