Odd Boy,

It didn't make sense until I realized your calculator failed you...

Quote Originally Posted by odd boy View Post
So if we assume that the ECT is 80 C and IAT is 30 C, the correction temperature will be 273.15+IAT+((ECT-IAT)*factor )==> 273.15+30+((80-30)*.6) = 347.15 K.

Now will assume that the IAT is -40 C, the new value will be 375.15 K.
I get:
273.15+30+((80-30)*.6) = 333.15K
273.15-40+((80+40)*.6) = 305.15K

1. When IAT = 30 C, corrected temp = 347.15 K :

g/cyl = VE*MAP/charge temperature ==> g/cyl = 80*35/347.15 = 8.06

2. When IAT = -40 C, corrected temp = 375.15 K :

g/cyl = VE*MAP/charge temperature ==> g/cyl = 80*35/375.15 = 7.46
80*35/333.15 = 8.40 g/cyl
80*35/305.15 = 9.17 g/cyl

(I know you are just using VE = 80 for example sake... the VE would be closer to something like 2-3 g*K/kPa.)

Regards
Joe