Page 2 of 3 FirstFirst 123 LastLast
Results 11 to 20 of 21

Thread: IAT question

  1. #11
    Joe (Moderator) joecar's Avatar
    Join Date
    Apr 2003
    Posts
    28,400

    Default

    Odd Boy,

    It didn't make sense until I realized your calculator failed you...

    Quote Originally Posted by odd boy View Post
    So if we assume that the ECT is 80 C and IAT is 30 C, the correction temperature will be 273.15+IAT+((ECT-IAT)*factor )==> 273.15+30+((80-30)*.6) = 347.15 K.

    Now will assume that the IAT is -40 C, the new value will be 375.15 K.
    I get:
    273.15+30+((80-30)*.6) = 333.15K
    273.15-40+((80+40)*.6) = 305.15K

    1. When IAT = 30 C, corrected temp = 347.15 K :

    g/cyl = VE*MAP/charge temperature ==> g/cyl = 80*35/347.15 = 8.06

    2. When IAT = -40 C, corrected temp = 375.15 K :

    g/cyl = VE*MAP/charge temperature ==> g/cyl = 80*35/375.15 = 7.46
    80*35/333.15 = 8.40 g/cyl
    80*35/305.15 = 9.17 g/cyl

    (I know you are just using VE = 80 for example sake... the VE would be closer to something like 2-3 g*K/kPa.)

    Regards
    Joe




  2. #12
    Lifetime Member
    Join Date
    Apr 2008
    Posts
    469

    Default

    It is sweet when u get confused and then clear. Correct me if I'm wrong, the elaboration I made is right (apart form the calculation part)
    Regards,

    Odd Boy

  3. #13
    Joe (Moderator) joecar's Avatar
    Join Date
    Apr 2003
    Posts
    28,400

    Default

    Your elaboration seems to be correct (you correctly used the concepts of temperature weighting and VE "actualization").

    Just remember that the VE table is not a percentage, but it is a normalized value having units g*K/kPa, and by applying charge pressure and charge temperature (under the conditions in which the charge entered the cylinder) you obtain the actual VE in g.

  4. #14
    Joe (Moderator) joecar's Avatar
    Join Date
    Apr 2003
    Posts
    28,400

    Default

    The result of your elaboration using correct calculation would be that at -40C the VE is almost 10% greater (richer) than at +30C.

  5. #15
    Lifetime Member
    Join Date
    Apr 2008
    Posts
    469

    Default

    Thanks, and think about posting my+ur write up with the required corrections and result
    Regards,

    Odd Boy

  6. #16
    Senior Member Sid447's Avatar
    Join Date
    Jul 2005
    Posts
    178

    Default

    As I understand it,

    Assuming the same atmospheric pressure and elevation; an IAT/OAT of 30c gives a higher Density Altitude than -40c does.
    Therefore if the D.A. is higher which means the air is thinner or has less oxygen, it doesn't require as much fuel (to maintain a decent AFR) and the power drops as a consequence of this.
    (Though there is some payback with less drag and thus less power required for a given speed depending on temp lapse rate).

    If the IAT is not signalling the PCM to decrease fuel in higher temps and increasing it in lower temps then maybe GM have got it wrong and need to compare notes with with an aero engine manufacturer like Pratt & Whitney.

    http://www.obd2crazy.com/techdiat.html

  7. #17
    Lifetime Member
    Join Date
    Apr 2008
    Posts
    469

    Default

    See what we came with, it is in line with ur understanding

    Quote Originally Posted by joecar View Post
    The result of your elaboration using correct calculation would be that at -40C the VE is almost 10% greater (richer) than at +30C.
    Use these two graphs as a future reference

    Click image for larger version. 

Name:	air-altitude-density.png 
Views:	272 
Size:	29.0 KB 
ID:	3856 Click image for larger version. 

Name:	Picture1.jpg 
Views:	285 
Size:	37.4 KB 
ID:	3857

    Should u have any question u can call me on +966504699641.
    Last edited by odd boy; September 4th, 2008 at 08:37 PM. Reason: to add two pics
    Regards,

    Odd Boy

  8. #18
    Joe (Moderator) joecar's Avatar
    Join Date
    Apr 2003
    Posts
    28,400

    Default

    The second graph shows it... cold air is denser than hot air... we don't even have to mention DA (to keep it simple).

    I don't follow why you say GM got it wrong...?

  9. #19
    Senior Member Sid447's Avatar
    Join Date
    Jul 2005
    Posts
    178

    Default

    Quote Originally Posted by joecar View Post
    The second graph shows it... cold air is denser than hot air... we don't even have to mention DA (to keep it simple).
    I don't follow why you say GM got it wrong...?
    Understanding DA is the whole foundation of air fuel mixture and performance!

    Anyway if post #10 is a fine example then I'll say no more.

  10. #20
    Joe (Moderator) joecar's Avatar
    Join Date
    Apr 2003
    Posts
    28,400

    Default

    I didn't see in that link anything that says differently that what was discussed... I am considering what you said and I didn't want to miss the point... ... I want to understand everyone's insight.

Page 2 of 3 FirstFirst 123 LastLast

Similar Threads

  1. Desired Airflow Question, not your normal question
    By Dale in forum General (Petrol, Gas, Ethanol)
    Replies: 25
    Last Post: October 1st, 2010, 11:10 AM
  2. Locked out timing question for boost setup question??
    By nitrorocket in forum General (Petrol, Gas, Ethanol)
    Replies: 13
    Last Post: September 13th, 2005, 03:22 PM

Posting Permissions

  • You may not post new threads
  • You may not post replies
  • You may not post attachments
  • You may not edit your posts
  •